document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579544>Question 579544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im having trouble in school and i need help on how to graph -3x+2y=-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371092 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3x%2B2y=-6 ALIGN=MIDDLE  ALT=\"-3x%2B2y=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > is a linear equation, and the graph will be a straight line.<BR>\n" );
document.write( "If you can plot two good points from that line, connecting them with a straight line is all you have to do.<BR>\n" );
document.write( "For each point you need and x value and the corresponding y value.<BR>\n" );
document.write( "Usually, choosing x=0 and/or y=0 is a good idea.<BR>\n" );
document.write( "For x=0, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2A0%2B2y=-6 ALIGN=MIDDLE  ALT=\"-3%2A0%2B2y=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y=-6 ALIGN=MIDDLE  ALT=\"2y=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y%2F2=-6%2F2 ALIGN=MIDDLE  ALT=\"2y%2F2=-6%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-3 ALIGN=MIDDLE  ALT=\"y=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "That gives you the point (0,-3)<BR>\n" );
document.write( "For x=0, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3x%2B2%2A0=-6 ALIGN=MIDDLE  ALT=\"-3x%2B2%2A0=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3x=-6 ALIGN=MIDDLE  ALT=\"-3x=-6\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-3x%29%2F%28-3%29=%28-6%29%2F%28-3%29 ALIGN=MIDDLE  ALT=\"%28-3x%29%2F%28-3%29=%28-6%29%2F%28-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=2 ALIGN=MIDDLE  ALT=\"x=2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "That gives you the point (2,0)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C-2%2C8%2C-5%2C5%2C%0D%0Agrid%281%29%2C%0D%0Ablue%28circle%280%2C-3%2C0.2%29%29%2Cblue%28circle%282%2C0%2C0.2%29%29%2C%0D%0Ablue%28line%28-2%2C-6%2C8%2C9%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > The line has a slope of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2 ALIGN=MIDDLE  ALT=\"3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > because the line rises 3 units as it runs 2 units to the right.<BR>\n" );
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