document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579849>Question 579849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If each side of a square is increased by 3 cm, the total area of both the new square and the original square will be 617 cm2 . Approximate to the nearest tenth of a centimeter the length of each side of the original square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371077 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let side of square be x<BR>\n" );
document.write( "area = l*w= x^2\r<BR>\n" );
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document.write( "3 is added to its side\r<BR>\n" );
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document.write( "Area of this square = (x+3)^2\r<BR>\n" );
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document.write( "x^2+(x+3)^2= 617 <BR>\n" );
document.write( "x^2+x^2+6x+9=617<BR>\n" );
document.write( "2x^2+6x-617+9=0<BR>\n" );
document.write( "2x^2+6x-608=0<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x^2+3x-304 =0\r<BR>\n" );
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document.write( "x^2+19x-16x-304=0\r<BR>\n" );
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document.write( "x(x+19)-16(x+19)=0<BR>\n" );
document.write( "(x+19)(x-16)=0\r<BR>\n" );
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document.write( "x=-19 OR 16\r<BR>\n" );
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document.write( "ignore negative\r<BR>\n" );
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document.write( "the length of side = 16cm </SPAN>\n" );
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