document.write( "Question 579431: how do you solve x=y+2 4y=3x-5 using substitution method? \n" ); document.write( "
Algebra.Com's Answer #371056 by ankor@dixie-net.com(22740)\"\" \"About 
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solve x=y+2 4y=3x-5 using substitution
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\n" ); document.write( "x = y + 2
\n" ); document.write( "4y = 3x - 5
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\n" ); document.write( "From the 1st equation we know that x = (y+2), therefore we can substitute (y+2) for x in the 2nd equation.
\n" ); document.write( "4y = 3(y+2) - 5
\n" ); document.write( "4y = 3y + 6 - 5
\n" ); document.write( "4y - 3y = 1
\n" ); document.write( "y = 1
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\n" ); document.write( "Use the 1st equation to find x, replace y with 1
\n" ); document.write( "x = 1 + 2
\n" ); document.write( "x = 3
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\n" ); document.write( "Check this in the 2nd equation by substituting 3 for x and 1 for y
\n" ); document.write( "4(1) = 3(3) - 5
\n" ); document.write( "4 = 9 - 5; confirms our solutions of x and y
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\n" ); document.write( "That was pretty easy, wasn't it? \n" ); document.write( "
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