document.write( "Question 579722: what are 2 consecutive even integers whose product plus two is 290 \n" ); document.write( "
Algebra.Com's Answer #371048 by mananth(16946) You can put this solution on YOUR website! let the integers be x & (x+2)\r \n" ); document.write( "\n" ); document.write( "x(x+2)+2=290\r \n" ); document.write( "\n" ); document.write( "x^2+2x+2=290\r \n" ); document.write( "\n" ); document.write( "Add -2 to both sides\r \n" ); document.write( "\n" ); document.write( "x^2+2x-288=0\r \n" ); document.write( "\n" ); document.write( "x^2+18x-16x-288=0\r \n" ); document.write( "\n" ); document.write( "x(x+18)-16(x+18)=0 \n" ); document.write( "(x+18)(x-16)=0\r \n" ); document.write( "\n" ); document.write( "x=-18, x=16\r \n" ); document.write( "\n" ); document.write( "The numbers are 16 & 18\r \n" ); document.write( "\n" ); document.write( "OR \n" ); document.write( "-18, -16 \n" ); document.write( " |