document.write( "Question 579722: what are 2 consecutive even integers whose product plus two is 290 \n" ); document.write( "
Algebra.Com's Answer #371048 by mananth(16946)\"\" \"About 
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let the integers be x & (x+2)\r
\n" ); document.write( "\n" ); document.write( "x(x+2)+2=290\r
\n" ); document.write( "\n" ); document.write( "x^2+2x+2=290\r
\n" ); document.write( "\n" ); document.write( "Add -2 to both sides\r
\n" ); document.write( "\n" ); document.write( "x^2+2x-288=0\r
\n" ); document.write( "\n" ); document.write( "x^2+18x-16x-288=0\r
\n" ); document.write( "\n" ); document.write( "x(x+18)-16(x+18)=0
\n" ); document.write( "(x+18)(x-16)=0\r
\n" ); document.write( "\n" ); document.write( "x=-18, x=16\r
\n" ); document.write( "\n" ); document.write( "The numbers are 16 & 18\r
\n" ); document.write( "\n" ); document.write( "OR
\n" ); document.write( "-18, -16
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