document.write( "Question 579436: A takes 10 days less than the time B to complete a work. If both A and B together can finish the work in 12 days, find the time taken by B to finish the work. \n" ); document.write( "
Algebra.Com's Answer #371018 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A takes 10 days less than the time B to complete a work. \n" ); document.write( " If both A and B together can finish the work in 12 days, find the time taken by B to finish the work. \n" ); document.write( ": \n" ); document.write( "Let b = time for B to complete the work \n" ); document.write( "then \n" ); document.write( "(b-10) = time for A to do it \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "A typical shared work equation \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply by b(b-10) \n" ); document.write( "b(b-10)* \n" ); document.write( "Cancel the denominators \n" ); document.write( "12(b-10) + 12b = b^2 - 10b \n" ); document.write( ": \n" ); document.write( "12b - 120 + 12b = b^2 - 10b \n" ); document.write( "Combine like terms on the right \n" ); document.write( "0 = b^2 -10b - 24b + 120 \n" ); document.write( "b^2 - 34b + 120 = 0 \n" ); document.write( "this will factor to \n" ); document.write( "(b-30)(b-4) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "b = 4 \n" ); document.write( "and \n" ); document.write( "b = 30 days, this is the only reasonable answer \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "See if checks out \n" ); document.write( "12/30 + 12/20 - \n" ); document.write( ".4 + .6 = 1, confirms our solution of b = 30 days \n" ); document.write( " |