document.write( "Question 579436: A takes 10 days less than the time B to complete a work. If both A and B together can finish the work in 12 days, find the time taken by B to finish the work. \n" ); document.write( "
Algebra.Com's Answer #371018 by ankor@dixie-net.com(22740)\"\" \"About 
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A takes 10 days less than the time B to complete a work.
\n" ); document.write( " If both A and B together can finish the work in 12 days, find the time taken by B to finish the work.
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\n" ); document.write( "Let b = time for B to complete the work
\n" ); document.write( "then
\n" ); document.write( "(b-10) = time for A to do it
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "A typical shared work equation
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\n" ); document.write( "\"12%2Fb\" + \"12%2F%28%28b-10%29%29\" = 1
\n" ); document.write( "Multiply by b(b-10)
\n" ); document.write( "b(b-10)*\"12%2Fb\" + b(b-10)*\"12%2F%28%28b-10%29%29\" = b(b-10)
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "12(b-10) + 12b = b^2 - 10b
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\n" ); document.write( "12b - 120 + 12b = b^2 - 10b
\n" ); document.write( "Combine like terms on the right
\n" ); document.write( "0 = b^2 -10b - 24b + 120
\n" ); document.write( "b^2 - 34b + 120 = 0
\n" ); document.write( "this will factor to
\n" ); document.write( "(b-30)(b-4) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "b = 4
\n" ); document.write( "and
\n" ); document.write( "b = 30 days, this is the only reasonable answer
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\n" ); document.write( ":
\n" ); document.write( "See if checks out
\n" ); document.write( "12/30 + 12/20 -
\n" ); document.write( ".4 + .6 = 1, confirms our solution of b = 30 days
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