document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579340>Question 579340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular lawn has a length of 6 m and a width that is twice its length.  What is the area of the lawn?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370967 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the width is twice the length, then the width is 2*6 = 12 meters. So L = 6, W = 12. Use these values to find the area A:\r<BR>\n" );
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document.write( "A = LW\r<BR>\n" );
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document.write( "A = 6*12\r<BR>\n" );
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document.write( "A = 72\r<BR>\n" );
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document.write( "So the area of the lawn is 72 square meters. </SPAN>\n" );
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