document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579324>Question 579324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3.	The probability that a bulb produced by a factory will fuse after certain period of time is 0.05. Find the probability that out of 5 such bulbs<BR>\n" );
document.write( "a.	None fuses<BR>\n" );
document.write( "b.	Not more than 2 fuse<BR>\n" );
document.write( "c.	More than 2 fuse<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370957 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The probability that a bulb produced by a factory will fuse after certain period of time is 0.05. Find the probability that out of 5 such bulbs<BR>\n" );
document.write( "a. P(None fuses) = 0.95^5 = 0.7738<BR>\n" );
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document.write( "b. P(Not more than 2 fuse) = binomcdf(5,0.05,2) = 0.9988<BR>\n" );
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document.write( "c. P(More than 2 fuse) = 1-0.9988 = 0.0012<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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