document.write( "Question 579361: Assume that the pointer can never lie on a border line. Find the following probabilities.\r
\n" );
document.write( "\n" );
document.write( "P(A), P(B), P(C), = 1st Wheel has 3 sections named A,B,C > I answered correctly 1/3 for each of those sections in the first wheel.-\r
\n" );
document.write( "\n" );
document.write( "P(D), P(E), P(F), = 2nd Wheel has 3 sections named D,E,F
\n" );
document.write( "P(G), P(H), P(I) = 3rd Wheel has 4 sections named G,H.I,J J was not included in the question to account for.\r
\n" );
document.write( "\n" );
document.write( "Since there are 3 wheels, I assumed each wheel was divided into sections, logically I presumed 3 part wheel, divided into thirds and so on.\r
\n" );
document.write( "\n" );
document.write( "I was correct for the first wheel and incorrect for the next two wheels. I initially thought thirds as well for the second wheel and fourths for the third wheel. \r
\n" );
document.write( "\n" );
document.write( "I know I am over thinking this, but cannot seem to determine the correct fractional makeup for the second and third wheels. Can someone help me understand this?\r
\n" );
document.write( "\n" );
document.write( "Thank you \n" );
document.write( "
Algebra.Com's Answer #370950 by Theo(13342)![]() ![]() You can put this solution on YOUR website! what was the exact wording of the problem? \n" ); document.write( "do the 3 wheels spin independently of each other? \n" ); document.write( "is this a joint probability, i.e. p(A) * p(D) * p(G)? \n" ); document.write( "your assumption should be correct if p(D) was only from the spin of the second wheel. \n" ); document.write( "same goes for p(G). \n" ); document.write( "p(A) would be 1/3 \n" ); document.write( "p(D) would be 1/3 \n" ); document.write( "p(G) would be 1/4 \n" ); document.write( "this is obviously not the case so there must be something to the problem that we're missing. \n" ); document.write( "send me the complete wording of the problem and also the solutions that are expected and i might be able to piece it together.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |