document.write( "Question 579345: if six times a number is added to 33, the result is 75. find the number
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Algebra.Com's Answer #370947 by Edwin McCravy(20056)\"\" \"About 
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six times a number is added to 33, the result is 75.
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document.write( "Replace the words \"a number\" by x\r\n" );
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\n" ); document.write( "six times x is added to 33, the result is 75.
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document.write( "Replace the words \"six times x\" by \"6x\r\n" );
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\n" ); document.write( "6x is added to 33, the result is 75.
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document.write( "When we add to a number we start with what we are adding to,\r\n" );
document.write( "and then we add to it.  Since we are adding to 33, we start with\r\n" );
document.write( "33 and then we add 6x to it, so replace \"6x added to 33\" by\r\n" );
document.write( "\"33 + 6x\".  The other tutor has it reversed.  It will give the same\r\n" );
document.write( "result, but it's not translated correctly. It should be 33 + 6x,\r\n" );
document.write( "not 6x + 33.  It won't make a difference since addition is \r\n" );
document.write( "commutative, but it would if it were subtracted, so it's a good idea\r\n" );
document.write( "to always translate in the correct order whether adding or subtracting.\r\n" );
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\n" ); document.write( "33 + 6x, the result is 75.
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document.write( "Replace the words \"the result is\" by an equal sign:\r\n" );
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\n" ); document.write( "33 + 6x = 75
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document.write( "Subtract 33 from both sides\r\n" );
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\n" ); document.write( " 6x = 42
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document.write( "Divide both sides by 6\r\n" );
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\n" ); document.write( " x = 7\r
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