document.write( "Question 579298: log(6)^x+log(6)^(x-9)=2
\n" ); document.write( "How do I solve for x?
\n" ); document.write( "please help
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Algebra.Com's Answer #370943 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Your notation is confusing. I'll assume you meant log base 6:
\n" ); document.write( "\"log%286%2Cx%29%2Blog%286%2C%28x-9%29%29=2\"
\n" ); document.write( "\"log%286%2Cx%28x-9%29%29=2\"
\n" ); document.write( "\"x%28x-9%29=6%5E2\"
\n" ); document.write( "\"x%5E2-9x=36\"
\n" ); document.write( "\"x%5E2-9x-36=0\"
\n" ); document.write( "\"%28x-12%29%28x%2B3%29=0\"
\n" ); document.write( "x = {-3, 12}
\n" ); document.write( "But, since you can't take the log of a negative number, the -3 is an extraneous answer -- throw it out leaving:
\n" ); document.write( "x = 12
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