document.write( "Question 579316: if three people are randomly selected, what is the probability at least two of them have the same birthday? \n" ); document.write( "
Algebra.Com's Answer #370936 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Eliminate leap year for simplicity. \n" ); document.write( "(365/365)*(364/365)*(363/365)=.9918 probability that none have the same birthday. \n" ); document.write( "1-.9918=.0082 the probability that at least two of them have the same birthday. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |