document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54917>Question 54917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are two types of fish in the lake.  fish type A has a current population of 5750 and is decreasing by 250 fish per year.  fish type B has a current population of 3500 and is increasin by 500 per year.  in how many years will the fish population in the lake be the same and what will the total fish population be? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37091 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are two types of fish in the lake. fish type A has a current population of 5750 and is decreasing by 250 fish per year. fish type B has a current population of 3500 and is increasin by 500 per year. in how many years will the fish population in the lake be the same and what will the total fish population be?<BR>\n" );
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document.write( "Let x be the number of years till the populations are equal.<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "5750-250x = 3500+500x<BR>\n" );
document.write( "2750=750x<BR>\n" );
document.write( "x=3 2/3 yrs<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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