document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579194>Question 579194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im having a very hard time figuring out how to do the substitution method the problem that im stuck on is x=5+y then the second part of the equation is 2x-3y=7 but im stuck because i dont understand how to do it <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370896 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=5+y<BR>\n" );
document.write( "2x-3y=7<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "2(5+y)-3y=7<BR>\n" );
document.write( "10+2y-3y=7<BR>\n" );
document.write( "-y=7-10<BR>\n" );
document.write( "-y=-3<BR>\n" );
document.write( "y=3<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "2x-3*3=7<BR>\n" );
document.write( "2x-9=7<BR>\n" );
document.write( "2x=7+9<BR>\n" );
document.write( "2x=16<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "x=5+y<BR>\n" );
document.write( "8=5+3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );