document.write( "Question 54790: Can someone help me on this problem?\r
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document.write( " Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil?\r
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document.write( " Thanks,
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document.write( " Sher \n" );
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Algebra.Com's Answer #37087 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil? \n" ); document.write( ": \n" ); document.write( "Let t = no. of hrs till Ching meets Phil \n" ); document.write( ": \n" ); document.write( "Let (t-1) = no. of hrs till Phil meets Ching \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "Ching's Dist + Phil's Dist = 380 \n" ); document.write( ": \n" ); document.write( " 50t + 60(t-1) = 380; multiplied what's inside the brackets \n" ); document.write( ": \n" ); document.write( " 50t + 60t - 60 = 380 \n" ); document.write( ": \n" ); document.write( "110t = 380 + 60; added 60 to both sides \n" ); document.write( ": \n" ); document.write( "110t = 440 \n" ); document.write( ": \n" ); document.write( "t = 440/110 \n" ); document.write( ": \n" ); document.write( "t = 4 hrs for Ching to meet Phil \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: (50*4) + (60*3) = 380 \n" ); document.write( " \n" ); document.write( " |