document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579095>Question 579095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of a number and the number decreased by 3 is 108. Find the two possible answers for the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370859 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be x<BR>\n" );
document.write( "x(x-3)=108\r<BR>\n" );
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document.write( "x^2-3x=108<BR>\n" );
document.write( "x^2-3x-108 =0\r<BR>\n" );
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document.write( "x^2-12x+9x-108=0\r<BR>\n" );
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document.write( "x(x-12)+9(x-12)=0\r<BR>\n" );
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document.write( "(x-12)(x+9)=0\r<BR>\n" );
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document.write( "x=12 OR -9 \r<BR>\n" );
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document.write( " </SPAN>\n" );
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