document.write( "Question 579097: Find two consecutive odd integers such that the square root of the larger is four less than the smaller. \n" ); document.write( "
Algebra.Com's Answer #370854 by dfrazzetto(283)![]() ![]() You can put this solution on YOUR website! Intuitively, we can guess it is 7 and 9, which works, but to solve it mathematically\r \n" ); document.write( "\n" ); document.write( "2n+1, 2n+3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Square both sides: \n" ); document.write( " \n" ); document.write( "2n+3 = 4n^2 -12n + 9\r \n" ); document.write( "\n" ); document.write( "4n^2 - 14n + 6 = 0; divide by 2 \n" ); document.write( " \n" ); document.write( "2n^2 - 7n + 3 = 0; factor: \n" ); document.write( " \n" ); document.write( "(2n - 1)(n - 3) = 0\r \n" ); document.write( "\n" ); document.write( "n = 1/2 or 3\r \n" ); document.write( "\n" ); document.write( "plugging 1/2 into original equations gives us 2 and 4 which are even, so throw that out\r \n" ); document.write( "\n" ); document.write( "plugging 3 into original equations gives us 7 and 9, which work\r \n" ); document.write( "\n" ); document.write( "
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