document.write( "Question 54833: Can someone help me solve this problem?\r
\n" ); document.write( "\n" ); document.write( " At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart?\r
\n" ); document.write( "\n" ); document.write( " Thanks, Lyn \n" ); document.write( "
Algebra.Com's Answer #37085 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart?
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\n" ); document.write( "North car DATA:
\n" ); document.write( "rate=55 mph ; time= x hrs. ; distance= 55x mi.
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\n" ); document.write( "South car DATA:
\n" ); document.write( "rate= 60 mph ; time= x-1 hrs ; distance = 60(x-1)=60x-60 miles
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\n" ); document.write( "EQUATION:
\n" ); document.write( "south distance+ north distace = 285 miles
\n" ); document.write( "60x-60+55x=285
\n" ); document.write( "115x=345
\n" ); document.write( "x=3 hrs
\n" ); document.write( "1:00p.m.+3 hrs. = 4:00p.m.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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