document.write( "Question 578998: 2(b+1)-(6+b)=-5 Justin had 35$ before spending q dollars on Jeans.how much money remains? The translation is ? Solve: 16(x+3)=4(4x+5)+28 \n" ); document.write( "
Algebra.Com's Answer #370825 by nyc_function(2741) You can put this solution on YOUR website! Solve for b:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(b+1)-(6+b)= -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2b + 2 - 6 - b = -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b - 4 = -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b = -5 + 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b = -1 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Justin had $35 before spending q dollars on Jeans. How much money remains? If he has $35 and spends q dollars, the remaining amount is (35 - q) dollars. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16(x+3)= 4(4x+5)+28 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16x + 48 = 16x + 20 + 28 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16x + 48 = 16x + 48 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16x - 16x = 48 - 48 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = 0 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do you see we have the same quantity on both sides of the equation? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means the answer will always be true for this equation. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Done! \n" ); document.write( " |