document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578753>Question 578753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is a question I can't figure out how to get started. I considered using the binomial formula but it looks like it would take ages to calculate, I must be missing the point!\r<BR>\n" );
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document.write( "Past car sales experience has shown that 22% of all luxury cars sold are black. If 45 recent sales of luxury cars are randomly selected. Find the following probabilities:<BR>\n" );
document.write( "1. At least 2 cars are black.<BR>\n" );
document.write( "2. Exactly 6 are black.  (I attempted this one using the binomial prob. formula and got 8.9417<BR>\n" );
document.write( "3. Between 1 and 4 cars (inclusive) are black.<BR>\n" );
document.write( "4. No more than 3 cars are black.<BR>\n" );
document.write( "5. More than 40 cars are not black.<BR>\n" );
document.write( "Guessing I have to begin with n, x, p and q.\r<BR>\n" );
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document.write( "Thanks for the guidance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370778 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> yes, you have to sum a few terms of the expansion (it shouldn't take \"ages\")\r<BR>\n" );
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document.write( "the expansion is ___ (Pb + Pn)^45 ___ (.22 + .78)^45\r<BR>\n" );
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document.write( "1. 43 (or less) are not black<BR>\n" );
document.write( "___ subtracting the last 3 terms from one ___  1 - {[(.78)^45] + 45[.22 (.78)^44] + 990[(.22)^2 (.78)^43]}\r<BR>\n" );
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document.write( "2.  45C6 [(.22)^6 (.78)^39] = .0572 (approx)\r<BR>\n" );
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document.write( "3.  sum those four terms\r<BR>\n" );
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document.write( "4.  see #1 ___ 42 (or more) are not black\r<BR>\n" );
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document.write( "5.  see #3 ___ 4 (or less) are black </SPAN>\n" );
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