document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578760>Question 578760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do i write the equation of a line that passes through (2,-9) and is perpendicular to the line (2x-9y=18) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370770 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perpendicular means you can swap the x and y coefficients and change one of the signs\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "9x + 2y = ?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "to find the new constant term, plug in the given point ___ 9(2) + 2(-9) = ? ___ 0 = ?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "9x + 2y = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "or, for those not comfortable with zero, ___ 2y = -9x ___ y = (-9/2)x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );