document.write( "Question 578607: please help me solve this question
\n" ); document.write( "4y-12=4x find the intercepts and then use them to graph the equation using the graphing tool to graph the line. use the intercepts when drawing a line. if only one intercept exists use it and another point to draw the line
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Algebra.Com's Answer #370739 by ankor@dixie-net.com(22740)\"\" \"About 
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4y-12=4x find the intercepts and then use them to graph the equation
\n" ); document.write( "Put the equation in the \"slope/intercept form\"
\n" ); document.write( "4y - 12 = 4x
\n" ); document.write( "4y = 4x + 12
\n" ); document.write( "divide both side side by 4
\n" ); document.write( "y = x + 3
\n" ); document.write( ":
\n" ); document.write( "The y intercept occurs when x = 0
\n" ); document.write( "y = 0 + 3
\n" ); document.write( " y = 3
\n" ); document.write( "the x intercept occurs when y = 0
\n" ); document.write( "x + 3 = 0
\n" ); document.write( "x = -3
\n" ); document.write( ":
\n" ); document.write( "Plot these two points: 0,3 and -3,0
\n" ); document.write( "should look like this
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-6%2C+6%2C+x%2B3%29+\"
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