document.write( "Question 578652: a boats crew rowed 9 miles down stream with a current, in 1.5hrs. the return trip upstream against current covered same distance but took 3 hours find crews row rate in still water and the rate of current \n" ); document.write( "
Algebra.Com's Answer #370710 by mananth(16946)\"\" \"About 
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Boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current , x-y 3 hours
\n" ); document.write( "with current , x+y 1.5 hours
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\n" ); document.write( "Distance = same= 9 miles
\n" ); document.write( "t=d/r against current
\n" ); document.write( "9.00 / ( x - y )= 3.00
\n" ); document.write( "9.00 ( x - y ) = 3.00
\n" ); document.write( "3.00 x - -3.00 y = 9.00 ....................1
\n" ); document.write( "
\n" ); document.write( "9.00 / ( x + y )= 1.50
\n" ); document.write( "1.50 ( x + y ) = 9.00
\n" ); document.write( "1.50 x + 1.50 y = 9.00 ...............2
\n" ); document.write( "Multiply (1) by 1.00
\n" ); document.write( "Multiply (2) by 2.00
\n" ); document.write( "we get
\n" ); document.write( "3.00 x + -3.00 y = 9.00
\n" ); document.write( "3.00 x + 3.00 y = 18.00
\n" ); document.write( "6.00 x = 27.00
\n" ); document.write( "/ 6.00
\n" ); document.write( "x = 4.5 mph
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3 x -3 y = 9
\n" ); document.write( "13.5 -3 y = 9
\n" ); document.write( "-3 y = 9 -13.5
\n" ); document.write( "-3 y = -4.5
\n" ); document.write( " y = 1.5 mph
\n" ); document.write( " Boat 4.5 mph
\n" ); document.write( " current 1.5 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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