document.write( "Question 578503: Andy canoed down river for two hours and returned in three hours. Andy's speed in still water is 2mph faster than the speed of the current. Find both speeds, write a system and then solve it. Thank you so much you are a life saver! \n" ); document.write( "
Algebra.Com's Answer #370673 by ankor@dixie-net.com(22740)\"\" \"About 
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Andy canoed down river for two hours and returned in three hours.
\n" ); document.write( " Andy's speed in still water is 2mph faster than the speed of the current.
\n" ); document.write( " Find both speeds, write a system and then solve it.
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\n" ); document.write( "Let s = still water speed
\n" ); document.write( "then
\n" ); document.write( "(s-2) = current speed
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\n" ); document.write( "Upstream speed
\n" ); document.write( "s - (s-2) = s - s + 2
\n" ); document.write( "2 mph is upstream speed
\n" ); document.write( ":
\n" ); document.write( "Downstream speed
\n" ); document.write( "s + (s-2) =
\n" ); document.write( "2s-2 mph is downstream speed
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\n" ); document.write( "The distance up and back is the same, write a distance equation:
\n" ); document.write( "Down dist = Up dist
\n" ); document.write( "2(2s-2) = 3(2)
\n" ); document.write( "4s - 4 = 6
\n" ); document.write( "4s = 6 + 4
\n" ); document.write( "s = 10/4
\n" ); document.write( "s = 2.5 mph in still water
\n" ); document.write( "and
\n" ); document.write( "2.5 - 2 = .5 mph is the current
\n" ); document.write( ":
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\n" ); document.write( "Check this by finding the distances, they should be the same
\n" ); document.write( "3(2.5-.5) = 6 mi
\n" ); document.write( "2(2.5+.5) = 6 mi\r
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