document.write( "Question 578449: Please help me solve the below algebra problem. The problem should read x to the 3/2 power=125... I tried to set up the problem the best way I could. Thank you :)\r
\n" ); document.write( "\n" ); document.write( "x^3/2=125
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Algebra.Com's Answer #370650 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
x^(3/2)=\"x%5E%283%2F2%29=x%5E1.5=125\"
\n" ); document.write( "The beauty of rational exponents is that they were defined so that the same properties for integer exponents that you knew still hold true. You do not even have to think of the fact that they could be written as roots.
\n" ); document.write( "The problem with those fractional exponents is that often I cannot get them to show properly in this website.
\n" ); document.write( "I we raise to the exponent 2/3 both sides of that equation, we get
\n" ); document.write( "\"%28x%5E%283%2F2%29%29%5E%282%2F3%29=+125%5E%282%2F3%29\" --> \"x%5E%28%283%2F2%29%282%2F3%29%29=125%5E%282%2F3%29\"
\n" ); document.write( "OK, I mean x^((3/2)(2/3))=125^(2/3)
\n" ); document.write( "Of course, \"%283%2F2%29%282%2F3%29=1\", so the equation simplifies to
\n" ); document.write( "x^1=125^(2/3) or x=125^(2/3)=\"root%283%2C125%5E2%29%5E2=%28root%283%2C125%29%29%5E2\"
\n" ); document.write( "That may look complicated, but \"125=5%5E3\", so
\n" ); document.write( "\"125%5E%282%2F3%29=%285%5E3%29%5E%282%2F3%29=5%5E%283%2A%282%2F3%29%29=5%5E2=25\"
\n" ); document.write( "So \"highlight%28x=25%29\"
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