document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578394>Question 578394</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me solve this algebra problem. I set up the problem the best way, I knew how. \r<BR>\n" );
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document.write( "1/4 =3- 2x-1/x+2\r<BR>\n" );
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document.write( "This problem is suppose to be set up as a fraction 1/4 and 2x-1/x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370637 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/4) =3- [(2x-1)/(x+2)]<BR>\n" );
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document.write( "Multiply thru by 4(x+2) to get:<BR>\n" );
document.write( "x+2 = 12(x+2) - (2x-1)<BR>\n" );
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document.write( "x+2 = 12x + 24 -3x + 1<BR>\n" );
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document.write( "x+2 = 9x + 25<BR>\n" );
document.write( "8x = -23<BR>\n" );
document.write( "x = -23/8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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