document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578380>Question 578380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Points A, B, C, and D are collinear. AB is 15 more than BC, and CD is 8 more than BC. If AD is 5 less than twice AB, what are the lengths of AB, BC, and CD? (hint: draw a diagram and use a variable to write an equation then solve)\r<BR>\n" );
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document.write( "I am having trouble figuring out the answer the this problem, I don't know how to get an equation to solve the lengths using the information I am given. Could you please help? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370636 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Points A, B, C, and D are collinear. AB is 15 more than BC, and CD is 8 more than BC. If AD is 5 less than twice AB, what are the lengths of AB, BC, and CD? (hint: draw a diagram and use a variable to write an equation then solve) <BR>\n" );
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document.write( "A................B........C..............D<BR>\n" );
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document.write( "AB =  BC + 15<BR>\n" );
document.write( "CD = BC + 8<BR>\n" );
document.write( "AD = 2*AB - 5<BR>\n" );
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document.write( "AD = AB + BC + CD<BR>\n" );
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document.write( "Substitute for AB and CD to get:<BR>\n" );
document.write( "AD = BC+15+BC+BC+8<BR>\n" );
document.write( "AD = 3BC+23<BR>\n" );
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document.write( "Also: AD = 2*AB-5<BR>\n" );
document.write( "So: AD = 2(BC+15)-5<BR>\n" );
document.write( "And: AD = 2*BC+25<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3BC+23 = 2BC+25<BR>\n" );
document.write( "BC = 2<BR>\n" );
document.write( "AB = BC+15 = 2+15 = 17<BR>\n" );
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document.write( "CD = 2BC+23<BR>\n" );
document.write( "So CD = 2*2+23 = 27<BR>\n" );
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document.write( "Finally:<BR>\n" );
document.write( "AD = AB + BC + CD<BR>\n" );
document.write( "AD = 15 + 2 + 27 = 44<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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