document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578054>Question 578054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the circle diameter is 26cm there is a rectangle in the circle and the short side of the rectangle is 10cm how do tou find the long side of the rectangle??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370621 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "The diagonal of the rectangle HAS to be the diameter of the circle, in this case 26cm, so:\r<BR>\n" );
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document.write( "It is a right triangle:\r<BR>\n" );
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document.write( "a=10cm<BR>\n" );
document.write( "b=?<BR>\n" );
document.write( "c=hypotenuse= 26\r<BR>\n" );
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document.write( "*using Pythagorean Theorem*\r<BR>\n" );
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document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "10^2+b^2=26^2<BR>\n" );
document.write( "100 = b^2 = 676\r<BR>\n" );
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document.write( "b^2 = 576  <BR>\n" );
document.write( "b= 24 cm<BR>\n" );
document.write( " </SPAN>\n" );
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