document.write( "Question 578146: Prove:
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Algebra.Com's Answer #370600 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "sin(x) + sin(3x) + sin(5x) ≟ \"sin%5E2%283x%29%2Fsin%28x%29\"\r\n" );
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document.write( "sin(3x-2x) + sin(3x) + sin(3x+2x)  \r\n" );
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document.write( "[sin(3x)cos(2x) - cos(3x)sin(2x)] + sin(3x) + [sin(3x)cos(2x) + cos(3x)sin(2x)] \r\n" );
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document.write( "sin(3x)cos(2x) - cos(3x)sin(2x) + sin(3x) + sin(3x)cos(2x) + cos(3x)sin(2x) \r\n" );
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document.write( "sin(3x)cos(2x) + sin(3x) + sin(3x)cos(2x)\r\n" );
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document.write( "2sin(3x)cos(2x) + sin(3x)\r\n" );
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document.write( "sin(3x)[2cos(2x) + 1]\r\n" );
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document.write( "sin(3x)[2(2cosē(x)-1) + 1]\r\n" );
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document.write( "sin(3x)[4cosē(x)- 2 + 1]\r\n" );
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document.write( "sin(3x)[4cosē(x)- 1]\r\n" );
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document.write( "sin(3x)[2cosē(x) + 2cosē(x) - 1]\r\n" );
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document.write( "sin(3x)[2cosē(x) + (2cosē(x) - 1)]\r\n" );
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document.write( "sin(3x)[2cosē(x) + cos(2x)]\r\n" );
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document.write( "sin(3x)[2cosē(x) + cos(2x)]\"%28sin%28x%29%2Fsin%28x%29%29\"\r\n" );
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document.write( "sin(3x)\"%28+++%28+2sin%28x%29cos%5E2%28x%29+%2B+cos%282x%29sin%28x%29+%29+++%2Fsin%28x%29+%29++\"\r\n" );
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document.write( "sin(3x)\r\n" );
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document.write( "sin(3x)\"+++%28%28+sin%282x%29cos%28x%29+%2B+cos%282x%29sin%28x%29+%29+++%2Fsin%28x%29%29+++\"\r\n" );
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document.write( "sin(3x)\"+++%28%28+sin%282x%2Bx%29+%29+++%2Fsin%28x%29+++%29\"\r\n" );
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document.write( "sin(3x)\"%28+++%28+sin%283x%29+%29+++%2Fsin%28x%29+++%29\"\r\n" );
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document.write( "\"sin%5E2%283x%29%2Fsin%28x%29\"\r\n" );
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document.write( "Edwin
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