document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578234>Question 578234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this linear system using the elimination method: 2x-3y=2<BR>\n" );
document.write( "                                                                      -5x+2y=-16\r<BR>\n" );
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document.write( "My work: 2x-3y=2 ..... 5(2x-3y=2)= 10x-15y=10<BR>\n" );
document.write( "........-5x+2y=-16 ... 2(-5x+2y=-16)=-10x+4y=-32<BR>\n" );
document.write( "...........................................-11y=-42...-11/-11= y...-42/-11=3/4<BR>\n" );
document.write( "Answer I got: y=3/4 One Solution<BR>\n" );
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document.write( "I have tried multiplying it like this: 5(2x-3y=2) and 2(-5x+2y=-16) to get rid of x, then I subtracted: -15y=10 and 4y=-32 and got -11y=-42, and to get y by its self, i divided -11 by -42 and it left me with y=3/4 and it's a one solution\r<BR>\n" );
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document.write( "But I am not sure if this is correct.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370585 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You made a mistake when you added -32 to 10. You got the incorrect value of -42 when it's really -22\r<BR>\n" );
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document.write( "So it should be \r<BR>\n" );
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document.write( "-11y = -22\r<BR>\n" );
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document.write( "and solving for y gets you \r<BR>\n" );
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document.write( "y = 2\r<BR>\n" );
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document.write( "Now that you have this y value, use it to find x to complete the answer. </SPAN>\n" );
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