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document.write( "The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle.\r
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document.write( "I worked this problem and I came up with 9 in. Hope I am right!! \n" );
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Algebra.Com's Answer #37056 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle. \n" ); document.write( "--------- \n" ); document.write( "Let the width be \"x\" \n" ); document.write( "Length = 2x+2 \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "52 = 2(3x+2) \n" ); document.write( "26=3x+2 \n" ); document.write( "3x=24 \n" ); document.write( "x=8 \n" ); document.write( "width = 8 inches \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |