document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=578188>Question 578188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> natural domain of the square root of 5+4x-x^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370531 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5+4x-x^2=-(x-5)(x+1) must be greater than or equal to zero, so the we solve 5+4x-x^2>=0 to get -1 <= x <= 5. </SPAN>\n" );
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