document.write( "Question 578001: You are hired to monitor quality control for a clothes manufacture. The manufacture claims that only 5% of jeans manufactured have a defect.\r
\n" ); document.write( "\n" ); document.write( "A.) using the manufactures claim, write P(no defect) and P(defect) as decimals.
\n" ); document.write( "B.) at a checkpoint, you choose six pairs of jeans at random and determine that two pairs have a defect. Find the probability of this happening by chance, using the probabilities you wrote in part a.
\n" ); document.write( "C.) using your results from part b, do you believe the manufactures claim about quality control? Explain \n" ); document.write( "

Algebra.Com's Answer #370463 by dfrazzetto(283) $\"\"$ $\"About$

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A) P(no defect) = 100% - 5% = 95% = .95
\n" ); document.write( " P(defect) = 5% = .05\r
\n" ); document.write( "\n" ); document.write( "B) 2 defective / 6 total = 33% = .33 which is much higher than the probability by chance asserted by the manufacturer\r
\n" ); document.write( "\n" ); document.write( "C) .33 is much larger than .05, so it would be hard to believe the manufacturers claim, but our sample size n=6 was very small, to get more accurate representation, would have been better to include a larger sample size, of at least n=20\r
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