document.write( "Question 54880: If I invest $25,000 in two different stocks. One earns 6.5% and the other earns 7.00%. If the total interest earnings for one year is 1683.75, how much is invested in each stock?\r
\n" );
document.write( "\n" );
document.write( "Stock X = ? = 6.5% interest
\n" );
document.write( "Stock Y = ? = 7.0% interest
\n" );
document.write( "Total = $25,000 = 1,683.75 Total interest\r
\n" );
document.write( "\n" );
document.write( "Please show me how to solve this problem. \n" );
document.write( "
Algebra.Com's Answer #37046 by tutorcecilia(2152) You can put this solution on YOUR website! Ax+By=C [Use the standand formula of a line] \n" ); document.write( "A=the rate, percent or cost of item A \n" ); document.write( "x=the amount or number of item A \n" ); document.write( "B=the rate, percent or cost of item B \n" ); document.write( "y=the rate, percent or cost of item B \n" ); document.write( "C=(the total amount)(average rate) \n" ); document.write( "x+y=C so y=(Total amount of C-x] or y=C-x [Substitution for the y variable] \n" ); document.write( ". \n" ); document.write( "(0.065)(x)+(0.07)(25,000-x)= 1683.75 [Plug-in the values] \n" ); document.write( "0.065x+1750-0.07-x= 1683.75 [Simplify] \n" ); document.write( "0.065x-0.07-x= 1683.75-1750 [Solve for x] \n" ); document.write( "-.005x=-66.26 \n" ); document.write( "x=$13,250 \n" ); document.write( ". \n" ); document.write( "(6.5%)($13,250)=(0.065)(13,250)=$861.25 invested at 6.5% \n" ); document.write( "(7.0%)($25,000-x)=0.07(25,000-13,250)=1750-927.50=$822.50 invested at 7.0% \n" ); document.write( "So, $861.25+$822.50=$1683.75 \n" ); document.write( " \n" ); document.write( " |