document.write( "Question 577963: A survey for brand recognition is done and it is determined that 70% of
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document.write( "consumers have heard of Dull Computer Company. A survey of 900
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document.write( "randomly selected consumers is to be conducted. For such groups of 900,
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document.write( "would it be unusual to get 527 consumers who recognize the Dull
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document.write( "Computer Company name. \n" );
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Algebra.Com's Answer #370434 by dfrazzetto(283)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "527/900 = 58.6%, which may be far enough away (11.4%) from 70% to make the p value smaller than 5%, but we need more information like standard deviation \n" ); document.write( " |