document.write( "Question 577959: Train a and b are traveling in the same direction on parallel tracks. Train a is traveling at 100 mph and train b is traveling at 120 mph. Train a passes a station at 7:25 am, train b passes the same station at 7:40 AM at what time will train b catch up with a.\r
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document.write( "I CAME UP WITH 8:05 AM \n" );
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Algebra.Com's Answer #370433 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! after passing the station, train a has a \n" ); document.write( "head start. In \n" ); document.write( "If I start a stopwatch when train b passes station, then \n" ); document.write( "let \n" ); document.write( "distance that b has to travel until they meet \n" ); document.write( "train b's equation: \n" ); document.write( " \n" ); document.write( "train a's equation: \n" ); document.write( " \n" ); document.write( "---------------- \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "They will meet in 1 hr and 15 min, which is \n" ); document.write( "7:40 AM + 1:15 = 8:55 AM \n" ); document.write( "----------------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |