document.write( "Question 577959: Train a and b are traveling in the same direction on parallel tracks. Train a is traveling at 100 mph and train b is traveling at 120 mph. Train a passes a station at 7:25 am, train b passes the same station at 7:40 AM at what time will train b catch up with a.\r
\n" ); document.write( "\n" ); document.write( "I CAME UP WITH 8:05 AM
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Algebra.Com's Answer #370433 by josmiceli(19441)\"\" \"About 
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after passing the station, train a has a \"+40+-+25+=+15+\" min
\n" ); document.write( "head start. In \"+15+\" min, train a travels \"+100%2A%281%2F4%29+=+25+\" mi
\n" ); document.write( "If I start a stopwatch when train b passes station, then
\n" ); document.write( "let \"+t+\" be the time for them to meet, and \"d\" be the
\n" ); document.write( "distance that b has to travel until they meet
\n" ); document.write( "train b's equation:
\n" ); document.write( "\"+d+=+120t+\"
\n" ); document.write( "train a's equation:
\n" ); document.write( "\"+d+-+25+=+100t+\"
\n" ); document.write( "----------------
\n" ); document.write( "By substitution:
\n" ); document.write( "\"+120t+-+25+=+100t+\"
\n" ); document.write( "\"+20t+=+25+\"
\n" ); document.write( "\"+t+=+5%2F4+\" hr
\n" ); document.write( "They will meet in 1 hr and 15 min, which is
\n" ); document.write( "7:40 AM + 1:15 = 8:55 AM
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\n" ); document.write( "check:
\n" ); document.write( "\"+d+=+120t+\"
\n" ); document.write( "\"+d+=+120%2A%285%2F4%29+\"
\n" ); document.write( "\"+d+=+150+\"
\n" ); document.write( "and
\n" ); document.write( "\"+d+-+25+=+100t+\"
\n" ); document.write( "\"+d+-+25+=+100%2A%285%2F4%29+\"
\n" ); document.write( "\"+d+=+25+%2B+125+\"
\n" ); document.write( "\"+d+=+150+\"
\n" ); document.write( "OK
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