document.write( "Question 54834: Can someone help me on this?\r
\n" ); document.write( "\n" ); document.write( " The length of a rectangular garden is 2 ft. less than 3 times its width. If the perimeter of the garden is 44 ft, find the dimensions of the garden.\r
\n" ); document.write( "\n" ); document.write( " Thanks, Lyn
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Algebra.Com's Answer #37040 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
LENGTH=3W-2
\n" ); document.write( "WIDTH=W
\n" ); document.write( "PERIMETER=2*LENGTH+2*WIDTH
\n" ); document.write( "44=2(3W-2)+2W
\n" ); document.write( "44=6W-4+2W
\n" ); document.write( "44+4=8W
\n" ); document.write( "48=8W
\n" ); document.write( "W=48/8
\n" ); document.write( "W=6 & L=3*6-2 OR L=18-2 L=16
\n" ); document.write( "PROOF
\n" ); document.write( "44=2*16+2*6
\n" ); document.write( "44=32+12
\n" ); document.write( "44=44
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