document.write( "Question 577908: I am trying to solve the quadratic equation using the method from India.\r
\n" ); document.write( "\n" ); document.write( "I need assistance with each step. \r
\n" ); document.write( "\n" ); document.write( "The problem is 2x^2-3x-5=0\r
\n" ); document.write( "\n" ); document.write( "There are 6 steps and I have gotten to step 3\r
\n" ); document.write( "\n" ); document.write( "Step 1 2x^-3x=5
\n" ); document.write( "Step 2 8x^2-12x=20
\n" ); document.write( "Step 3 -3 is the original x term, therefore:
\n" ); document.write( " 8x^2-12x+9=29
\n" ); document.write( "Step 4, now I am to take the square root of each side. This is where I am confused, need help here through step 6.
\n" ); document.write( "

Algebra.Com's Answer #370389 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The problem is 2x^2-3x-5=0
\n" ); document.write( "There are 6 steps and I have gotten to step 3
\n" ); document.write( "Step 1 2x^2-3x=5
\n" ); document.write( "Question: Why do you multiply by 4?
\n" ); document.write( "Step 2 8x^2-12x=20
\n" ); document.write( "Step 3 -3 is the original x term, therefore:
\n" ); document.write( "8x^2-12x+9=29
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\n" ); document.write( "I don't think your 3rd step is correct.
\n" ); document.write( "According to your step 4 you need to complete the
\n" ); document.write( "square in step 3. That would be as follows:
\n" ); document.write( "8x^2-12x = 20
\n" ); document.write( "x^2 - (3/2)x = (5/2)
\n" ); document.write( "Competing the square you would get:
\n" ); document.write( "x^2 - (3/2)x + (3/4)^2 = (5/2) + (3/4)^2
\n" ); document.write( "Now you are ready to factor and then take the square root of both sides.
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\n" ); document.write( "Step 4, now I am to take the square root of each side.
\n" ); document.write( "(x-(3/4))^2 = (49/16)
\n" ); document.write( "(x-(3/4)) = +-7/4
\n" ); document.write( "x = (7/4)+(3/4) or x = -(7/4)+(3/4)
\n" ); document.write( "x = 5/2 or x = -1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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