document.write( "Question 577857: Given P(A)=0.2; P(B) = 0.5, P(A|B) = 0.3:\r
\n" );
document.write( "\n" );
document.write( "(a) Compute P(A and B).
\n" );
document.write( "(b) Compute P(A or B).\r
\n" );
document.write( "\n" );
document.write( " P(A) = 0.2; P(B) = 0.5; PA\B) = 0.3;\r
\n" );
document.write( "\n" );
document.write( "Compute P(A and B)
\n" );
document.write( "Note = P(A) = 1 P(A)
\n" );
document.write( " 0.2 =1 P(A)
\n" );
document.write( " .2 = 1.0 P(A)\r
\n" );
document.write( "\n" );
document.write( "Please help me with this problem. So I can understand what I am doing.\r
\n" );
document.write( "\n" );
document.write( "Thanks
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #370375 by spunky(1)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "P(A) = 0.2, P(B) = 0.5, P(A\B) = 0.3:\r \n" ); document.write( "\n" ); document.write( "P(A\B) = P(A and B) P(B) \n" ); document.write( " 0.3 = P(A and B) 0.5 \n" ); document.write( " 0.15 P(A and B) \n" ); document.write( "P(A and B) = 0.15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B. P(A or B) = P(A) + P(B) - P(A and B) \n" ); document.write( " 0.2 + 0.5 - 0.15 \n" ); document.write( " 0.70 - 0.15 = 0.55 \n" ); document.write( " |