document.write( "Question 577374: 1-125a^3 \n" ); document.write( "
Algebra.Com's Answer #370357 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to factor this\r
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\n" ); document.write( "\n" ); document.write( "\"1-125a%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%281%29%5E3-%285a%29%5E3\" Rewrite \"1\" as \"%281%29%5E3\". Rewrite \"125a%5E3\" as \"%285a%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%281-5a%29%28%281%29%5E2%2B%281%29%285a%29%2B%285a%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281-5a%29%281%2B5a%2B25a%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"1-125a%5E3\" factors to \"%281-5a%29%281%2B5a%2B25a%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"1-125a%5E3=%281-5a%29%281%2B5a%2B25a%5E2%29\"
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