document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=577817>Question 577817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 1 m narrower than its long, and one of its diagonals is 2 m longer than the width of the rectangle. what is the length of the diagonal. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370328 by </B><A HREF=/tutors/aboutme.mpl?userid=rachitaagarwal93><B>rachitaagarwal93(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rachitaagarwal93><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rachitaagarwal93><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let length be xm then width =(x-1)m and one of diagonal =(x-1+2)m =(x+1)m<BR>\n" );
document.write( "now by pythogorous theorum digonal^2=length^2+width^2<BR>\n" );
document.write( "substuting the values (x+1)^2=x^2+(x-1)^2 or x^2-4x=0 orx(x-4)=0 it gives x=4m<BR>\n" );
document.write( "therefore length of rectangle=4m so width is=4-1=3m<BR>\n" );
document.write( "and hence diagonal=3+2=5m </SPAN>\n" );
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