document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=577820>Question 577820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complimentry. The sum of the measure of the first angle and half the second angle is 69degrees. Find the measures of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #370326 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=370326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 angles are complementary is their sum is 90 degrees, so:\r<BR>\n" );
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document.write( "a + b = 90\r<BR>\n" );
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document.write( "a + b/2 = 69             system of equations, multiply bottom by -1\r<BR>\n" );
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document.write( "a + b = 90<BR>\n" );
document.write( "-a -b/2 = -69             add<BR>\n" );
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document.write( "b - b/2 = 21<BR>\n" );
document.write( "b/2 = 21<BR>\n" );
document.write( "b = 21(2) = 42\r<BR>\n" );
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document.write( "a + 42 = 90<BR>\n" );
document.write( "a = 90 - 42 = 48\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "a + b/2 = 69\r<BR>\n" );
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document.write( "48 + 42/2 = 69<BR>\n" );
document.write( "48 + 21 = 69<BR>\n" );
document.write( "69=69 &#8730;\r<BR>\n" );
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document.write( " </SPAN>\n" );
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