document.write( "Question 577612: In three days Carter drove 2196 miles in 36 hours behind the wheel. The first day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than on the first day, then how many hours did he drive each day?\r
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document.write( "Here is what I have so far:\r
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document.write( "Let x= hours day 1
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document.write( "Let y= hours day 2
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document.write( "Let z= hours day 3\r
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document.write( "x+y+z=2196\r
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document.write( "day 1= 64x
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document.write( "day 2= 62y
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document.write( "day 3= 58z\r
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document.write( "z= x+4\r
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document.write( "64x+62y+58(x+4)=2196
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document.write( "64x+62y+58x+232=2196
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document.write( "and then
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document.write( "122x+62y=1964\r
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document.write( "and after that I am completely stuck...
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Algebra.Com's Answer #370263 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let x= hours day 1 \n" ); document.write( "Let y= hours day 2 \n" ); document.write( "Let z= hours day 3\r \n" ); document.write( "\n" ); document.write( "x+y+z=2196\r \n" ); document.write( "\n" ); document.write( "day 1= 64x \n" ); document.write( "day 2= 62y \n" ); document.write( "day 3= 58z\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y+z=36 \n" ); document.write( "y=36-x-z\r \n" ); document.write( "\n" ); document.write( "64x+62y+58z= 2196\r \n" ); document.write( "\n" ); document.write( "64x+62(36-x-z)+58z= 2196 \n" ); document.write( "64x+62*36-62x-62z+58z=2196 \n" ); document.write( "2x-4z=-2232+2196 \n" ); document.write( "2x-4z=-36\r \n" ); document.write( "\n" ); document.write( "Now z= x+4 \n" ); document.write( "2x-4(x+4)=-36 \n" ); document.write( "2x-4x-16=-36 \n" ); document.write( "-2x=-20 \n" ); document.write( "/-2 \n" ); document.write( "x=10 hours first day \n" ); document.write( "z=x+4 = 14 hours \n" ); document.write( "y=12 hours \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |