document.write( "Question 577656: I am working on algebra homework involving circles and identifying the center and radius.\r
\n" ); document.write( "\n" ); document.write( "I got part of this equation correct, some of it by guessing.
\n" ); document.write( "I need assistance figuring out the radius please.\r
\n" ); document.write( "\n" ); document.write( "My problem is as follows.
\n" ); document.write( "Identify the center & radius of the circle written in standard form.
\n" ); document.write( "Center (x,y) ( , )
\n" ); document.write( "Radius, \r
\n" ); document.write( "\n" ); document.write( "x^2 + (y+5)^2=27\r
\n" ); document.write( "\n" ); document.write( "I figured out/guessed, (x,y) is (0, -5)
\n" ); document.write( "I dont know how to figure the radius. I have tried 27, 27^2, 729, all incorrect
\n" ); document.write( "I am at a loss. I would appreciate any help possible. Thank you.
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Algebra.Com's Answer #370243 by nyc_function(2741)\"\" \"About 
You can put this solution on YOUR website!
You are right in saying that the center is the point (0,-5).\r
\n" ); document.write( "\n" ); document.write( "The radius is:\r
\n" ); document.write( "\n" ); document.write( "r^2 = 27\r
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\n" ); document.write( "\n" ); document.write( "Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "sqrt{r^2} = sqrt{27}\r
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\n" ); document.write( "\n" ); document.write( "r = sqrt{9}*sqrt{3}\r
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\n" ); document.write( "\n" ); document.write( "r = 3(sqrt{3}).\r
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\n" ); document.write( "\n" ); document.write( "The radius is 3 times the square root of 3.\r
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