document.write( "Question 577641: Hi, i am in year 12 maths B and don't understand how to use logarithms at all. An example of a question i am having difficulty with is: \r
\n" ); document.write( "\n" ); document.write( "Use logarithms to solve:\r
\n" ); document.write( "\n" ); document.write( "7^x = 1/343\r
\n" ); document.write( "\n" ); document.write( "Thankyou for your help in advance \n" ); document.write( "
Algebra.Com's Answer #370241 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Use logarithms to solve:\r
\n" ); document.write( "\n" ); document.write( "7^x = 1/343
\n" ); document.write( "-----------
\n" ); document.write( "The name \"logarithms\" is unfortunate. Logs are exponents. If the name were something that implied that, it would be less confusing.
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\n" ); document.write( "7^x = 1/343
\n" ); document.write( "There are 2 ways to approach this.
\n" ); document.write( "If you know that 343 = 7^3, then 1/343 = 7^(-3)
\n" ); document.write( "Then, 7^(-3) = 1/343, and x = -3
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\n" ); document.write( "The 2nd method is the base change formula.
\n" ); document.write( "7^x = 1/343
\n" ); document.write( "x*log(7) = log(1/343)
\n" ); document.write( "x = log(1/343)/log(7)
\n" ); document.write( "x = -3
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