document.write( "Question 5549: the width of a rectangle is 3 inches less than its length. The area of the rectangle is 340 square inches. What are the length and widthof the rectangle? \n" ); document.write( "
Algebra.Com's Answer #370196 by ankor@dixie-net.com(22740)\"\" \"About 
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he width of a rectangle is 3 inches less than its length.
\n" ); document.write( " The area of the rectangle is 340 square inches.
\n" ); document.write( " What are the length and width of the rectangle?
\n" ); document.write( ":
\n" ); document.write( "We know the Area is: L * W = 340
\n" ); document.write( "Given that,\"The width of a rectangle is 3 inches less than its length.\"
\n" ); document.write( "W = L - 3
\n" ); document.write( "Replace W with (L-3) in the area equation
\n" ); document.write( "L * (L-3) = 340
\n" ); document.write( "L^2 - 3L = 340
\n" ); document.write( "L^2 - 3L - 340 = 0; a quadratic equation
\n" ); document.write( "factors to
\n" ); document.write( "(L-20)(L+17) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "L = 20 inches is the Length
\n" ); document.write( "then
\n" ); document.write( "w = 20 - 3 = 17 inches is the width
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check by finding the area: 20 * 17 = 340 \n" ); document.write( "
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