document.write( "Question 577536: what is the answer to x^2+8x+15?
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Algebra.Com's Answer #370187 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2%2B8x%2B15\", we can see that the first coefficient is \"1\", the second coefficient is \"8\", and the last term is \"15\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"15\" to get \"%281%29%2815%29=15\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"15\" (the previous product) and add to the second coefficient \"8\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"15\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"15\":\r
\n" ); document.write( "\n" ); document.write( "1,3,5,15\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"15\".\r
\n" ); document.write( "\n" ); document.write( "1*15 = 15
\n" ); document.write( "3*5 = 15
\n" ); document.write( "(-1)*(-15) = 15
\n" ); document.write( "(-3)*(-5) = 15\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"8\":\r
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First NumberSecond NumberSum
1151+15=16
353+5=8
-1-15-1+(-15)=-16
-3-5-3+(-5)=-8
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"3\" and \"5\" add to \"8\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"3\" and \"5\" both multiply to \"15\" and add to \"8\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"8x\" with \"3x%2B5x\". Remember, \"3\" and \"5\" add to \"8\". So this shows us that \"3x%2B5x=8x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%283x%2B5x%29%2B15\" Replace the second term \"8x\" with \"3x%2B5x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B3x%29%2B%285x%2B15%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B3%29%2B%285x%2B15%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B3%29%2B5%28x%2B3%29\" Factor out \"5\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%28x%2B3%29\" Combine like terms. Or factor out the common term \"x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2%2B8x%2B15\" factors to \"%28x%2B5%29%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2%2B8x%2B15=%28x%2B5%29%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x%2B5%29%28x%2B3%29\" to get \"x%5E2%2B8x%2B15\" or by graphing the original expression and the answer (the two graphs should be identical).
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