document.write( "Question 576912: The length of a rectangle is 3cm less than twice the width. The perimeter of the rectangle is 72cm. Find the length and width of the rectangle.\r
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document.write( "I need help setting up the correct formula to find the answer, I tried a couple and my answer is still wrong. \n" );
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Algebra.Com's Answer #370154 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 3cm less than twice the width. \n" ); document.write( " The perimeter of the rectangle is 72cm. \n" ); document.write( " Find the length and width of the rectangle. \n" ); document.write( ": \n" ); document.write( "The perimeter \n" ); document.write( "2L + 2W = 72 \n" ); document.write( ": \n" ); document.write( "It say's,\"The length of a rectangle is 3cm less than twice the width.\". therefore: \n" ); document.write( "L = 2W - 3 \n" ); document.write( ": \n" ); document.write( "Replace L in the 1st equation with (2W-3) \n" ); document.write( "2(2W-3) + 2W = 72 \n" ); document.write( "Mult what's inside the brackets \n" ); document.write( "4W - 6 + 2W = 72 \n" ); document.write( "4W + 2W = 72 + 6 \n" ); document.write( "6W = 78 \n" ); document.write( "W = \n" ); document.write( "W = 13 \n" ); document.write( ": \n" ); document.write( "Now you should be able to find L. Then check the perimeter with those values \n" ); document.write( " |