document.write( "Question 576912: The length of a rectangle is 3cm less than twice the width. The perimeter of the rectangle is 72cm. Find the length and width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "I need help setting up the correct formula to find the answer, I tried a couple and my answer is still wrong.
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Algebra.Com's Answer #370154 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangle is 3cm less than twice the width.
\n" ); document.write( " The perimeter of the rectangle is 72cm.
\n" ); document.write( " Find the length and width of the rectangle.
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\n" ); document.write( "The perimeter
\n" ); document.write( "2L + 2W = 72
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\n" ); document.write( "It say's,\"The length of a rectangle is 3cm less than twice the width.\". therefore:
\n" ); document.write( "L = 2W - 3
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\n" ); document.write( "Replace L in the 1st equation with (2W-3)
\n" ); document.write( "2(2W-3) + 2W = 72
\n" ); document.write( "Mult what's inside the brackets
\n" ); document.write( "4W - 6 + 2W = 72
\n" ); document.write( "4W + 2W = 72 + 6
\n" ); document.write( "6W = 78
\n" ); document.write( "W = \"78%2F6\"
\n" ); document.write( "W = 13
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\n" ); document.write( "Now you should be able to find L. Then check the perimeter with those values
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