document.write( "Question 577136: x+y=10
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Algebra.Com's Answer #370080 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Start with the given system of equations:\r
\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=10%2Cx-y=2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2By%29%2B%28x-1y%29=%2810%29%2B%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%2B1x%29%2B%281y%2B-1y%29=10%2B2\" Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B0y=12\" Combine like terms. Notice how the y terms cancel out.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=12\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2812%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=6\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=10\" Now go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"6%2By=10\" Plug in \"x=6\".\r
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\n" ); document.write( "\n" ); document.write( "\"6%2By=10\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"y=10-6\" Subtract \"6\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=6\" and \"y=4\".\r
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\n" ); document.write( "\n" ); document.write( "Which form the ordered pair .\r
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\n" ); document.write( "\n" ); document.write( "This means that the system is consistent and independent.\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"x%2By=10\" (red) and \"x-y=2\" (green) \r
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