document.write( "Question 577037: Construct the 95% and the 99% confidence intervals for the population proportion p using the sample statistics below:\r
\n" ); document.write( "\n" ); document.write( "p=0.627
\n" ); document.write( "q=0.373
\n" ); document.write( "n=4351\r
\n" ); document.write( "\n" ); document.write( "The 95% confidence interval for the population proportion p is (____, ____)\r
\n" ); document.write( "\n" ); document.write( "The 99% confidence interval for the population proportion p is (_____,____)\r
\n" ); document.write( "\n" ); document.write( "Which interval is wider?\r
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Algebra.Com's Answer #370044 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
95% confidence interval\r
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\n" ); document.write( "\n" ); document.write( "( p - z*sqrt( (p(1-p))/n ), p + z*sqrt( (p(1-p))/n ) )\r
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\n" ); document.write( "\n" ); document.write( "( 0.627 - 1.95996*sqrt( (0.627(1-0.627))/4351 ), 0.627 + 1.95996*sqrt( (0.627(1-0.627))/4351 ) )\r
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\n" ); document.write( "\n" ); document.write( "( 0.6126, 0.6414 )\r
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\n" ); document.write( "\n" ); document.write( "So the 95% confidence interval is ( 0.6126, 0.6414 ), it's width is 0.6414 - 0.6126 = 0.0288\r
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\n" ); document.write( "\n" ); document.write( "99% confidence interval\r
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\n" ); document.write( "\n" ); document.write( "( p - z*sqrt( (p(1-p))/n ), p + z*sqrt( (p(1-p))/n ) )\r
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\n" ); document.write( "\n" ); document.write( "( 0.627 - 2.5758*sqrt( (0.627(1-0.627))/4351 ), 0.627 + 2.5758*sqrt( (0.627(1-0.627))/4351 ) )\r
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\n" ); document.write( "\n" ); document.write( "( 0.6081, 0.6459 )\r
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\n" ); document.write( "\n" ); document.write( "So the 99% confidence interval is ( 0.6081, 0.6459 ), it's width is 0.6459 - 0.6081 = 0.0378\r
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\n" ); document.write( "\n" ); document.write( "So the 99% confidence interval is wider
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