document.write( "Question 54626: Write an expression for the area of an isosceles triangle and simplify. The base is 1/2Y and the height is 2/5y + 4 \n" ); document.write( "
Algebra.Com's Answer #37003 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Write an expression for the area of an isosceles triangle and simplify. The base is 1/2Y and the height is 2/5y + 4 \n" ); document.write( "AREA=BASE*HT/2=(Y/2)(2Y/5 +4)/2=Y(2Y+5)/(2*2)=(2Y^2+5Y)/4 \n" ); document.write( " |